"A velocity of an object at a given moment in time"
when an item moves with a uniform pace, then its on the spot pace may be equal to the usual pace.
Suppose a ball is thrown vertically upwards. Find how fast it is going at a specific moment, given the time of 4 seconds.
The ball's position is given by the function:
x(t) = -5t² + 20t + 10
Solution:
Step # 1: Use the Instantaneous velocity formula:
vint = dx(t) / dt
Step # 2: Put the values into the formula:
vint = d(-5t² + 20t + 10) / dt
Step # 3: Simplify the derivative
vint = -10t + 20
Now, substitute the value of t (t = 4):
vint = (-10 * 4) + 20
vint = -20 m/s
Hence, at 4 seconds, the instantaneous velocity of the ball is -20 m/s. This negative value indicates that the ball is moving downward at 20 meters per second after 4 seconds of flight.
