Kinematics is a subfield of physics that evolved in classical mechanics. In physics, it shows the motion of elements, ourselves, as well as our bodies' machine running without regard for the forces that drive them. more particularly, kinematics shows velocity, acceleration, and momentum as the have a look at of the objects in motion. For educational purposes, move as river water. Whether you are managing object or factor motion, this kinematics calculator helps you to determine the kinetics.
Known as a set of formulation that use the 5 kinematic variables provided, the kinetic formulation
\(s\) = Displacement
\(t\) = Time taken
\(u\) = Initial velocity
\(v\) = Final velocity
\(a\) = Constant acceleration
$$ v = u + at $$ $$ s = ut + \frac {1}{2}at^2 $$ $$ v^2 = u^2 + 2as $$ $$ s = (\frac {v + u}{2}) t $$
Example:
An object starts with a velocity of \(5 \, \text{m/s}\), and after \(10 \, \text{s}\), it attains a velocity of \(25 \, \text{m/s}\). Determine the acceleration and the distance covered by the object.
Solution:
Given:
\(u = 5 \, \text{m/s}\) (initial velocity)
\(v = 25 \, \text{m/s}\) (final velocity)
\(t = 10 \, \text{s}\) (time)
Step 1: Find the acceleration using the first equation of motion:
\(v = u + at\)
Substitute the values:
\(25 = 5 + a(10)\)
\(25 - 5 = 10a\)
\(20 = 10a\)
\(a = \frac{20}{10}\)
\(a = 2 \, \text{m/s}^2\)
Step 2: Find the distance using the second equation of motion:
\(S = ut + \frac{1}{2}at^2\)
Substitute the values:
\(S = (5)(10) + \frac{1}{2}(2)(10)^2\)
\(S = 50 + \frac{1}{2}(2)(100)\)
\(S = 50 + 100\)
\(S = 150 \, \text{m}\)
Final Answer:
Acceleration, \(a = 2 \, \text{m/s}^2\)
Distance covered, \(S = 150 \, \text{m}\)
The acceleration is the charge of exchange of speed of a transferring object. honestly, dividing the rate with the time taken by an item gives the acceleration of the object.
yes, the time is a kinematic variable. There are different quantities which includes acceleration, velocity & displacement which can be related to the motion of the object.
