Normal Force Calculator

Ordinary pressure?

The ordinary force is exerted on an item by means of a surface. as an example, you have got a tumbler and you placed it on a table, and the gravitational force pulls the glass downward. To forestall the glass from taking place the table exerts a pressure on it. This pressure that is exerted with the aid of the desk is known as the regular pressure. it's far denoted via \(F_N\) or N and the unit that is used for the normal pressure is Newton. This everyday pressure follows the precept of Newton's third law of movement.

Everyday force formula:

The method that is used for knowing the ordinary pressure on a factor this is placed on a horizontal floor is as follows:\(Normal\ Force\ =\ F_N = m.g\)

Where,

• m is consultant of the mass of an object
• g is the gravitational acceleration

Normal pressure Examples:

1. Instance 1: A box of mass five kg is resting on a horizontal floor. Calculate the regular force exerted with the aid of the surface at the box.

Solution:

Mass = \(m = 5 \, \text{kg}\)

Gravitational acceleration = \(g = 9.8 \, \text{m/s}^2\)

The formula for normal force on a horizontal surface is:

\(F_N = m \cdot g\)

Substitute the values into the formula:

\(F_N = 5 \cdot 9.8 = 49 \, \text{N}\)

The normal force exerted by the surface is \(49 \, \text{N}\).

1. Example 2: A crate of mass 15 kg is placed on an inclined plane at an angle of \(30^\circ\) to the horizontal. Find the normal force acting on the crate.

Solution:

Given:

• Mass = \(m = 15 \, \text{kg}\)
• Gravitational acceleration = \(g = 9.8 \, \text{m/s}^2\)
• Angle = \(\theta = 30^\circ\)

The formula for normal force on an incline is:

\(F_N = m \cdot g \cdot \cos(\theta)\)

Substitute the values into the formula:

\(F_N = 15 \cdot 9.8 \cdot \cos(30^\circ)\)

\(F_N = 15 \cdot 9.8 \cdot 0.866\)

\(F_N \approx 127.1 \, \text{N}\)

The normal force acting on the crate is approximately \(127.1 \, \text{N}\).

1. Example 3: A person of mass 70 kg stands in an elevator accelerating upwards with an acceleration of \(2 \, \text{m/s}^2\). What is the normal force acting on the person?

Solution:

Given:

• Mass = \(m = 70 \, \text{kg}\)
• Gravitational acceleration = \(g = 9.8 \, \text{m/s}^2\)
• Acceleration of the elevator = \(a = 2 \, \text{m/s}^2\)

The formula for normal force when accelerating upwards is:

\(F_N = m \cdot (g + a)\)

Substitute the values into the formula:

\(F_N = 70 \cdot (9.8 + 2)\)

\(F_N = 70 \cdot 11.8\)

\(F_N = 826 \, \text{N}\)

The normal force acting on the person is \(826 \, \text{N}\).