Enter any two given values into the SOHCAHTOA calculator to find a missing sides and an angle of the right triangle.
This calculator uses the SOH.CAH.TOA mnemonic method to solve the sides and angles of a right triangle. It provides step-by-step calculations using the SOHCAHTOA formula, which we are going to mention below.
SOH CAH TOA is a mnemonic way used to remember the formulas for main trigonometric ratios including sine (sin), cosine (cos), and tangent (tan). Here's what each letter in the acronym stands for:
It refers to which of the trig ratios can be used for finding missing sides and angles based on the formulas below.
SOH: (Sin (θ)) = Opposite Hypotenuse
CAH: (Cos (θ)) = Adjacent Hypotenuse
TOA: (Tan (θ)) = Opposite Adjacent
Even the sohcahtoa calculator implements these formulas to calculate missing sides and angles.
In the Diagram:
It is easy to remember the sequence of Sin, Cos, and Tan. You need to try memorable phrases such as:
“Oscar Had A Heap Of Apples”
It implies to right angle trig functions as:
There are steps to work out the unknown sides of a right-angled triangle:
We have a right triangle with a following measurement:
Find the missing side that is opposite to the acute angle.
We are looking for the opposite side by having the hypotenuse, so use the SOH formula. Hence put the values and get to know the missing side.
30° = Opposite 13 cm
We also know that Sin (30°) is a fixed value (0.5)
0.5 = Opposite 13 cm
Now, to find the missing opposite side, we can multiply both sides of the equation by 13 cm.
Opposite = 0.5 * 13 cm
Opposite = 6.5 cm
$$ {\displaystyle \sin \theta } $$ | $$ {\displaystyle \cos \theta } $$ | $$ {\displaystyle \tan \theta =\sin \theta {\Big /}\cos \theta } $$ | |
0° = 0 radians | $$ {\displaystyle {\frac {\sqrt {\mathbf {\color {blue}{0}} }}{2}}=\;\;0} $$ | $$ {\displaystyle {\frac {\sqrt {\mathbf {\color {red}{4}} }}{2}}=\;\;1} $$ | $$ {\displaystyle \;\;0\;\;{\Big /}\;\;1\;\;=\;\;0} $$ |
30° = π/6 radians | $$ {\displaystyle {\frac {\sqrt {\mathbf {\color {teal}{1}} }}{2}}=\;\,{\frac {1}{2}}} $$ | $$ {\displaystyle {\frac {\sqrt {\mathbf {\color {orange}{3}} }}{2}}} $$ | $$ {\displaystyle \;\,{\frac {1}{2}}\;{\Big /}{\frac {\sqrt {3}}{2}}={\frac {1}{\sqrt {3}}}} $$ |
45° = π/4 radians | $$ {\displaystyle {\frac {\sqrt {\mathbf {\color {green}{2}} }}{2}}={\frac {1}{\sqrt {2}}}} $$ | $$ {\displaystyle {\frac {\sqrt {\mathbf {\color {green}{2}} }}{2}}={\frac {1}{\sqrt {2}}}} $$ | $$ {\displaystyle {\frac {1}{\sqrt {2}}}{\Big /}{\frac {1}{\sqrt {2}}}=\;\;1} $$ |
60° = π/3 radians | $${\displaystyle {\frac {\sqrt {\mathbf {\color {orange}{3}} }}{2}}} $$ | $$ {\displaystyle {\frac {\sqrt {\mathbf {\color {teal}{1}} }}{2}}=\;{\frac {1}{2}}} $$ | $$ {\displaystyle {\frac {\sqrt {3}}{2}}{\Big /}\;{\frac {1}{2}}\;\,={\sqrt {3}}} $$ |
90° = π/2 radians | $$ {\displaystyle {\frac {\sqrt {\mathbf {\color {red}{4}} }}{2}}=\;\,1} $$ | $$ {\displaystyle {\frac {\sqrt {\mathbf {\color {blue}{0}} }}{2}}=\;\,0} $$ | $$ {1{\Big /}0\;\;= \text {Undefined}} $$ |